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Answer/Explaination
:
ibj!gsjfoet
(Exp):
++*p++ will be parse in the given order
*p that is value at the location currently pointed by p will be taken
++*p the retrieved value will be incremented
when ; is encountered the location will be incremented that is p++
will be executed
Hence, in the while loop initial value pointed by p is 'h', which is
changed to 'i' by
executing ++*p and pointer moves to point, 'a' which is similarly
changed to 'b' and so
on. Similarly blank space is converted to '!'. Thus, we obtain value
in p becomes
"ibj!gsjfoet" and since p reaches '\0' and p1 points to p
thus p1doesnot print anything.
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