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Answer/Explaination
:
30,20,10
(Exp):
'{' introduces new block and thus new scope. In the innermost block i
is
declared as,
const volatile unsigned
which is a valid declaration. i is assumed of type int. So printf
prints 30. In
the next block, i has value 20 and so printf prints 20. In the
outermost
block, i is declared as extern, so no storage space is allocated for
it. After
compilation is over the linker resolves it to global variable i (since
it is the
only variable visible there). So it prints i's value as 10.
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